Probability and Statistics

Katherine Rawlins
August 7, 2000, River Falls, WI

Outline:


Introduction to Statistics

Two broad categories of probabilities:
  1. Measured emperically

  2. (Ex: 18 out of every 1,000 teenage girls get pregnant every year. 85% of small businesses fail within the first 5 years.)
  3. Computed from assumptions or models

  4. (Ex: The probability of rolling a six on a die is 1/6. The particle has a probability of 0.01 for tunneling through the barrier.)
AMANDA: "The probability of a neutrino interacting with ice or rock and triggering our detector is...."
Which type is it? 

...So, what are my chances of being hit by a stray neutrino?

And why can nobody give me a straight answer to this question?

To answer this question, we need 2 pieces of information:

Both of these numbers CHANGE with ENERGY.


Flux:

At solar neutrino energies (MeV):     10^12 nus/sq.m/sec
(There are 10^4 square cm in a square meter...) = 10^8 nus/sq.cm/sec

At 1 GeV:    1 nus/sq.cm/sec

At higher energies:
A steeply falling spectrum!
Nu flux
from: "Cosmic Rays" by Michael W. Friedlander, 1989.

The important line here is the H(x5), representing proton cosmic rays.  Notice that both the x and y axes are on a log scale.



Interaction Probability

At solar energies: Pretty darn low (one in 10^18, or probability of 10^-18)

At 1 GeV:    One in 10^12 (probability = 10^-12)

At 1 TeV:    One in 10^6 (probability = 10^-6)

At 1 PeV:    One in 1000 (probability = 10^-3)

Nu probability
from: "Cosmic Rays and Particle Physics" by Thomas K. Gaisser, 1990.



So, the number of interactions per square centimeter per second is: The size of AMANDA is about 1 square kilometer = 10^10 square cm.
(This is the "interaction volume", not the physical size)

The size of a person is about 1 square meter = 10^4 square cm.

The number of seconds in a year is about 3 x 10^7 sec/year.

Use these to compute the number of neutrinos that interact in AMANDA or you each year.
Keep in mind these are all order of magnitude estimates.


Addition and Multiplication of Probabilities

EXAMPLE 1a: "What is the probability that I will die on a Tuesday in September?"

Assume: Consider an ensemble of universes.

ensemble1



tuesandsept

Answer:
        Probability (Tues. AND Sept.) 
                                =
        Probability (Tues.) X Probability (Sept.)
...and in general:
 
        Probability (A  AND  B) 
                                =
        Probability (A)   X   Probability (B)

EXAMPLE 1b: "What is the probability that I will die on a Tuesday or a Wednesday?"

Make the same assumptions (all days of the week equally likely) and again consider the ensemble of universes.

tuesorweds

Answer:

        Probability (Tues. OR Weds.) 
                                =
        Probability (Tues.) + Probability (Weds.)
...and in general:
        Probability (A  OR  B) 
                                =
        Probability (A)   +   Probability (B)

EXAMPLE 1c: "What is the probability that I will die on a Tuesday or in September?"

This one's a little trickier. It's an "OR" question, but the probabilities do NOT just add up. Why? Look again at the ensemble of universes.

tuesorsept

Some of the universes will be counted twice! Instead, you have to compute the total amount of "white space" or universes that fulfil neither criteria, and subtract this fraction from one.

This time:

        Probability (Tues. OR Sept.) 
                                =
        1 - { Probability(not Tues) x Probability(not Sept) }

EXAMPLE 2: "What are the odds that my high school sweetheart becomes a telemarketer and calls me?"

We need to know: Then:
P = (P_tele) (P_area) {(P_homelisted) (P_home)  + (P_worklisted) (P_work)}(P_sweet)

EXAMPLE 3: "What are the odds that there exists intelligent life elsewhere in our galaxy capable of communicating with us?"

We need to know: Then:
Ncivilizations =        R*  fp  Ne  fl  fi  fc  L

The Drake Equation:
Ncivilizations =        R*  fp  Ne  fl  fi  fc  L
Written down in 1961 by Frank Drake, radio astronomer who conducted the first radio search for extraterrestrial life (Project Ozma) at NRAO.

Has been used ever since... we can well estimate the first three numbers, but can only guess at the others!


EXAMPLE 4: The "Birthday Problem":

In a room of N people, what is the probability that two have the same birthday? How big does N have to be before the probability passes 50/50?

Solution:
It's actually easier to do the inverse problem... What is the probability that no two people have the same birthday?...

Then the answer will be:

P(somebody shares a birthday) = 
        1 - P(nobody shares)

No two people share a birthday:

Person 2 does not share a birthday with Person 1
AND
Person 3 does not share a birthday with Person 1 OR Person 2,
AND
Person 4 does not share a birthday with Person 1 OR Person 2 OR Person 3,
AND
.....
Person N does not share a birthday with Person 1 OR Person 2 OR Person 3 OR.... OR Person N-1.

Notice that this is just a big combination of AND (multiplying) and OR (adding)! 


Let's compute each one:

In general: P (x shares with y) = P(x,y) = 1/365.
I'll call P (x does not share with y) = P(not x,y) = 1 - P(x,y)

P (not 2, 1)            = 1 - 1/365                             
                        = 364/365

P (not 3, 1 or 2)       = 1 - P(3,1 or 2)
                        = 1 - ( P(3,1) + P(3,2) )
                        = 1 - 1/365 - 1/365     
                        = 363/365

P (not 4, 1 or 2 or 3)  
                        = 1 - P(4,1 or 2 or 3)
                        = 1 -  ( P(4,1) + P(4,2) + P(4,3) )
                        = 1 - 1/365 - 1/365 - 1/365
                        = 362/365
....
Following this pattern,
P (not N, anybody else) = (365 - N + 1)/365

and so...
P (no two people share) =
    (364/365) x 
        (363/365) x 
            (362/365) x
                .....                                   
                    (365 - N + 2)/365 x
                        (365 - N + 1)/365

        (364 x 363 x 362 x ... x 365 - N + 1)
=    ---------------------------------------
                        (365)^N


P (somebody does share) = 1 - this.


from http://www.mste.uiuc.edu/reese/birthday/intro.html

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